sscanf hex ints into array of ints vs. unsigned chars

I am converting a string representation of a mac address into an array of UINT8s defined as unsigned char. I am curious why sscanf() will read all 0s when I read into an array of UINT8s and actual values when I read into an array of regular 32 bit ints. Its almost like it's chopping off the 8 bits of the wrong end of the int.

char strMAC = "11:22:33:AA:BB:CC";

typedef unsigned char UINT8;
UINT8 uMAC[6];

int iMAC[6];

sscanf( (const char*) strMac, 
        "%x:%x:%x:%x:%x:%x", 
        &uMAC[0], &uMAC[1], &uMAC[2], &uMAC[3], &uMAC[4], &uMAC[5] );
printf( "%x:%x:%x:%x:%x:%x", 
        uMAC[0], uMAC[1], uMAC[2], uMAC[3], uMAC[4], uMAC[5] );
// output: 0:0:0:0:0:0

sscanf( (const char*) strMac, 
        "%x:%x:%x:%x:%x:%x", 
        &iMAC[0], &iMAC[1], &iMAC[2], &iMAC[3], &iMAC[4], &iMAC[5] );
printf( "%x:%x:%x:%x:%x:%x", 
        iMAC[0], iMAC[1], iMAC[2], iMAC[3], iMAC[4], iMAC[5] );
// output: 11:22:33:AA:BB:CC

via Chebli Mohamed